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Algebra II

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A rock is thrown upward with a velocity of 19 meters per second from the top of a 21 meter high cliff and it misses the cliff on the way back down. When will the rock be 11 meters from the water below?

  • Algebra II -

    the height h at time t is

    h(t) = 21 + 19t - 4.9t^2
    so, plug in h=11 and solve for t:

    11 = 21 + 19t - 4.9t^2
    t ~= 4.35 sec

  • Algebra II -

    5.93

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