# calculus

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use implicit differentiation to find dy/dx . Then evaluate the derivative function at the designated point.
log (xy)= 2; (4, 25)

• calculus -

log(xy) = 2
1/(xy) (y + xy') = 0
1/x + 1/y y' = 0
y' = -y/x

Or, going about it another way,

logx + logy = 2
1/x + 1/y y' = 0
y' = -y/x

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