A system at equilibrium contains iodine at a pressure of 0.21 and iodine at a pressure of 0.23 . The system is then compressed to half its volume.Find the pressure diiodine of when the system returns to equilibrium.

Find the pressure of when the system returns to equilibrium.

It still isn't clear. You have two pressures for the same thing.

To find the pressure of diiodine (I2) when the system returns to equilibrium after being compressed, we need to use the concept of the equilibrium constant and Le Chatelier's principle. Here's how you can solve the problem step by step:

1. To start, write down the balanced chemical equation for the reaction involving iodine (I2) and diiodine (I2):
I2 ⇌ 2I

2. Now, let's define the equilibrium constant (Kp) for this reaction:
Kp = [I]^2 / [I2]

where [I] represents the concentration (pressure in this case) of iodine and [I2] represents the concentration (pressure in this case) of diiodine. Since we are given the pressures of iodine (0.21) and iodine (0.23), we can substitute these values into the equation:
Kp = (0.21)^2 / 0.23

3. Next, apply Le Chatelier's principle. When the system is compressed to half its volume, the pressure of both iodine and diiodine will increase. However, since iodine is in the numerator of the equilibrium constant expression, an increase in its pressure will cause the equilibrium to shift in the reverse direction to maintain the equilibrium constant. As a result, the pressure of diiodine (I2) will decrease.

4. Now, let's determine the new pressure of diiodine (I2) after the system returns to equilibrium. Since the system returned to equilibrium, the value of the equilibrium constant (Kp) remains the same. We can set up the following equation:
Kp = (0.21)^2 / P

where P represents the new pressure of diiodine.

5. Rearrange the equation to solve for P:
P = (0.21)^2 / Kp

Substitute the value of Kp from step 2 into the equation:
P = (0.21)^2 / ((0.21)^2 / 0.23)

Simplify the equation:
P = (0.21)^2 × (0.23 / (0.21)^2)

Calculate the value:
P = 0.23

The pressure of diiodine (I2) when the system returns to equilibrium after being compressed is 0.23.