college algebra
posted by Anonymous .
Solving for a variable
4x^2+3y=y+1/3 I'm stuck thanks

If all you need to do is solve for x and y then this is what I would do:
first solving for y
4x^2+3y=y+(1/3) multiply everything by 3 to get rid of (1/3)
12x^2+9y=3y then isolate y
(12x^2)/(6)=y
then solving for x
go back a few steps to get 12x^2=6y (this is just rearranging the y= equation)
solve that for x and you should get x=sqrt(y/2)
i hope this helps it seems to simple for college algebra, but there you go. 
the 4th line should have been
12x^2+9y=3y + 1
you probably wanted to solve for y, thus expressing it as a function:
6y = 12x^2 + 1
y = 2x^2 + 1/6
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