college algebra
posted by Anonymous
Axis symmetry x=3 passing through (3,1) and (1,9)
Not sure how to solve

JJ
(3,1) is the vertex of the parabola.
(1,9) and (5,9)
y = ax^2 + bx + c
Substitue in the point (3,1)
1 = a(9) +b(3) +c
Do the same for (1,9) and then again for (5,9)
You will have 3 equations and 3 variables. Solve for a, b, c.
There is also a formula to find the equation using the vertex and 1 point. you should be able to find it in your textbook or using a google search.
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