college algebra
posted by Anonymous .
Axis of symmerty x=3 passing through (3,1) and (1,9)
What is the best way to solve?

X = Xv = h = 3.
V(h,k)= V(3,1).
P(1,9)
Y = a(xh)^2 + k
Y = a(13)^2 + 1 = 9.
4a + 1 = 9
4a = 91 = 8
a = 2.
Eq: Y = 2(x3)^2 + 1
Axis: D(h,Y1), V(h,k), F(h,Y2).
Axis: D(3,Y1), V(3,1), F(3,Y2).
DV = kY1 = 1/4a = 1/8
1  Y1 = 1/8
Y1 = 7/8.
VF = Y2k = 1/4a = 1/8
Y21 = 1/8
Y2 = 1 1/8 = 9/8.