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A pulley is suspended by a Cord (C). on one end of the pulley there is a 1.2 kg block and on the other is a 3.2 kg block.Determine the tension in this cord after the masses are released and before one hits the ground. Ignore the mass of the pulley and cords

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    Solve these two simultaneous equations with unknowns a (acceleration) and T (tension).

    M1*g - T = M1*a
    T - M2*g = M2*a

    This leads to
    a = [(M1 -M2)/(M1 +M2)]*g
    T = [2*M1*M2/(M1+M2)]*g

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