Chemistry

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At a particular temperature, 13.7 mol of SO3 is placed into a 3.9-L rigid container, and the SO3 dissociates by the reaction given below.
2 SO3(g) 2 SO2(g) + O2(g)
At equilibrium, 3.8 mol of SO2 is present. Calculate K for this reaction.

  • Chemistry -

    13.7mol/3.9L = about 3.5
    3.8/3.9 = about0.97
    You need to do these more accurately.

    ........SO3 ==> 2SO2 + O2
    I.......3.5.......0......0
    C.......-2x.....2x.......x
    E......3.5-2x...2x........x

    The problem tells you that at equilibrium (SO2) = 2x = 3.8/3.9 = 0.974M

    Knowing x, you can calculate SO2m O2, and SO3, then substitute into the Kc expression and solve for Kc.

  • Chemistry -

    it says my answer is still wrong. I got 0.017683 but it says the right answer is 0.071777081878092.

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