science
posted by Fatima .
a particle is projected vertically upward with the velocity u m/s and after t(s) another particle is projected upwards from the same point and with the same initial velocity. proof that the particle will meet after a lapes of (u/g + t/2)seconds from the instance of the first particle.

Using t for time, and s for the delay,
ut  (g/2)t^2 = u(ts)  (g/2)(ts)^2
ut  (g/2)t^2 = ut  us + gst  (g/2)t^2  (g/2)s^2
(g/2)s^2  us + gst = 0
gst = us + (g/2)s^2
t = u/g + s/2
reverting to the t notation originally used, tada! 
thank u very much steve...am grateful

Thanks bro
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