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Three circles, each with a radius of 10, are mutually tangent to each other. The area enclosed by the three circles can be written as abã−cƒÎ, where a, b and c are positive integers, and b is not divisible by a square of a prime. What is the value of a+b+c?

  • MATH -

    Join the centers of the 3 triangles to form an equilateral triangle with sides length 20.
    The area enclosed by the 3 triangles will be the area of this triangle minus the area
    of 3 sectors of the circles with central angles of 60 degrees. Thus the area of the
    enclosed region will be

    (1/2)*(20)*(20*sin(60)) - 3*(60/360)*pi*10^2 =

    200*(sqrt(3) /2) - 50*pi = 100*sqrt(3) - 50*pi.

    So a + b + c = 100 + 3 + 50 = 153.

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