Physics (Acceleration)

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Determine the final velocity of a proton that has an initial velocity of 2.35 x 10^5 m/s, and then is accelerated uniformly in an electric field at the rate of -1.10 x x 10^12 m/s squared for 1.50 x 10^-7 s.

  • Physics (Acceleration) -

    V = Vo + a*t.
    V=2.35*10^5 -1.1*10^12*1.5*10^-7=
    70000m/s.

  • Physics (Acceleration) -

    21

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