math30
posted by alejandro .
The Mean and the Standard Deviation
Last year, golfers at Smith Ranch golf course had a mean score of 41 and a standard deviation of 2 on the first nine holes of the course, and a mean of 38 and a standard deviation of 1.8 on the last nine holes. One afternoon, Nathan scored 39 on the first nine holes and 37 on the last nine. On which half of the course did Nathan golf better, relative to the other golfers? Remember that in golf it is better to have a low score. Explain.
Respond to this Question
Similar Questions

Statistics
1) A Motor Company has purchased steel parts from a supplier for several years and has found that 10% of the parts must be returned because they are defective. An order of 25 parts is received. What are the mean and standard deviation … 
Stastics
When we convert xvalue to z score and use Standard Normal distribution, which of the following statements is true? 
statistics
A sample of 134 golfers showed that their average score on a particular golf course was 87.43 with a standard deviation of 4.53. Answer each of the following (show all work and state the final answer to at least two decimal places.): … 
statistics
Three students take equivalent stress tests. Which is the highest relative score? 
statistics
Three students take equivalent stress tests. Which is the highest relative score? 
statistics
A sample of 106 golfers showed that their average score on a particular golf course was 87.98 with a standard deviation of 5.39. Answer each of the following (show all work and state the final answer to at least two decimal places.): … 
statistics
So if a depression scale has 30 items in it, and if an individual gets a score of 20 what does this mean? 
statistics
So if a scale has 30 items in it, and if an individual gets a score of 20 what does this mean? 
Data Management
Emilio has played ten rounds of golf this season. His mean score is 80 and standard deviation is 4. Assume Emilio's golf scores are normally distributed. a) Find the 95% confidence interval of Emilio's mean golf score b)Find the 95% … 
Algebra
Use a calculator to find the mean and standard deviation of the data. Round to the nearest tenth. 6,7,19,7,18,7 A. mean = 9; standard deviation = 26.4 B. mean = 11.9; standard deviation = 26.4 C. mean = 10.6; standard deviation = 6.1 …