pre-cal

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solve for all values in [0,2pie)
2cos^2x-5sinx+1=0

  • pre-cal -

    2(1-sin^2)-5sin+1=0
    2sin^2 + 5sin - 3 = 0
    (2sin-1)(sin+3) = 0
    so, sinx = 1/2 or -3
    -3 is not allowed, so
    sinx = 1/2: x = pi/6 or 5pi/6

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