I'm feeling pretty stupid right now because I can't remember how to do these. if f(x) = (2x-5)/(x^2-4), write an equation of the tangent line to f at point x=0. *How do I find the slope of the tangent line?
2^(x^2 - 35)= 4^x How do I solve this? The x^2 is messing me up. So far I have: ln(2^(x^2-35))=ln(4^x) (x^2-35)ln 2= xln4 x^2ln 2 - 35ln2= xln4 x^2ln 2- xln4= 35ln2 x(xln2 - ln4)= 35ln2 I would have taken the log base 2 of each side,
Assume that x, y, and z are positive numbers. Use the properties of logarithms to write the expression 2lnx - 6lny + 1/3ln e^12 as a simplified logarithm. Is this 2lnx - 6lny + 4, or can it be simplified further?