Chemistry

posted by .

Acetic acid ionizes in water as follows:

CH3COOH + H2O CH3COO– + H3O+

Fewer than 1% of ethanoic acid molecules are ionized at any instant. The acetate ion (CH3COO– ) is therefore ____.

A.a poor hydrogen-ion acceptor
B.a good hydrogen-ion acceptor
C.a poor hydrogen-ion donor
D.a good hydrogen-ion donor

I posted this question ealier and have reread some information and I am getting 2 answers between B and C?
Can anyone clarify? Thank you in advance...

  • Chemistry -

    Okay, I didn't read the question correctly/carefully. I thought the question was asking about acetic acid, not the ion; I apologize about that. Acetic acid is a weak acid, and thus a poor hydrogen ion donor. Its conjugate base, the acetate ion, would be a good hydrogen-ion acceptor.

  • Chemistry -

    Correction, it would be a poor hydrogen-ion acceptor.


    Google: wisconsin acid and base conjugates

    Take a look at wisconsin's website to understand what the correct answer will be.

  • Chemistry -

    A is the correct answer.

  • Chemistry -

    Hello,
    A is NOT the correct answer, i just took this test and it is...
    Fewer than 1% of ethanoic acid molecules are ionized at any instant. The acetate ion (CH3COO– ) is therefore ____. (1 point)
    (0 pts) a poor hydrogen-ion acceptor
    (1 pt) a good hydrogen-ion acceptor
    (0 pts) a poor hydrogen-ion donor
    (0 pts) a good hydrogen-ion donor

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. chemistry

    A student prepared a .10M solution of acidic acid. Acidic acid has a Ka of 1.75 x 10-3. What are the hydronium ion concentration and the PH of the solution?
  2. Chem

    Write the equation for dissocation of acetic acid in water: My Answer: CH2COOH + H2O <=> H3O+ + CH3COO- Equation for hydrolysis of acetate anion in water: My Answer: CH3COO- + H2O <=> CH3COOH + OH- Now, using the above …
  3. Chemistry

    25.0 mL of 0.100 M acetic acid (Ka= 1.8 x 10^-5) is titrated with 0.100 M NaOH. Calculate the pH after the addtion of 27.00 mL of 0.100M NaOH. my work CH3COOH + H2O <-> H3O^+ + CH3COO^- 25mL x 0.100 mmol/ml = 2.5mmol CH3COOH …
  4. Chemistry

    acetic acid ionizes in water according to the following equation: CH3COOH<-->H+ + CH3COO- if the solution is .766 M acetic acid, what is the concentration of H+?
  5. Chemistry

    Acetic acid dissociates/ionizes itself as follows: CH3COOH(aq) ⇔ H+(aq) + CH3COO-(aq) If you add sodium acetate, CH3COONa, to the solution: a) a precipitate will be formed b) more acetic acid will be ionized c) the concentration …
  6. Chemistry

    Acetic acid ionizes in water as follows: CH3COOH + H2O --> CH3COO– + H3O+ <-- Fewer than 1% of ethanoic acid molecules are ionized at any instant. The acetate ion (CH3COO– ) is therefore ____. A.a poor hydrogen-ion acceptor …
  7. Chemistry

    Measuring the conductivity of an aqueous solution in which 0.0200 mol CH3COOH has been dissolved in 1.00 L of solution shows that 2.96 % of acetic acid molecules have ionized to CH3COO- ions and H3O+ ions. Calculate the equilibrium …
  8. chemistry

    Calculate the approximate pH of a 0.1 M solution of ethanoic acid at 298 K, given that the dissociation constant, Ka, is 1.75 x 10-5 mol/L at 298 K.Ethanoic acid dissociates in aqueous solution as follows: CH3COOH(aq) + H2O H3O+(aq) …
  9. chemistry

    What is the equilibrium expression for the following acid dissociation reaction?
  10. science ap chemistry

    What is the equilibrium expression for the following acid dissociation reaction?

More Similar Questions