mathsurgently needed
posted by Anonymous .
In right angled triangle ABC angle B=90 degree
and AB= root 34 unit. The coordinates of point B and Care (4,2)and (1,y) respectively.
If area of triangle ABC = 17 sq.units, then find value of y.

area = (1/2)(BC)(AB)
17 = (1/2)(√(5^2 + (2y)^2 ) (√34
34/√34 = √(25 + 4  4y + y^2)
square both sides
34 = 29  4y + y^2
y^2  4y  5 = 0
(y5)(y+1) = 0
y = 5 or y = 1
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