Calculus

posted by .

Approximate the sum

Sigma (lower n = 0; upper infinity) (17/3)*(-1/2)^n

  • Calculus -

    I agree with Steve. All of these questions and no answers look like homework dumping.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Calculus

    Determine the convergence or divergence of the series. Find the limit. Indicate the test that was used and justify your answer by showing evidence why the test succeeds or fails. Sigma (lower index n = 1; upper index infinity) 12/[n(n+3)]
  2. Calculus

    Test for convergence or divergence. Indicate the test that was used and justify your answer. Sigma (lower index n = 4; upper index infinity) 1/(3n^2-2n-15)
  3. Calculus

    Use the Direct Comparison Test to determine the convergence or divergence of the series. Justify your answer and show all of your work. Sigma (lower index n = 1; upper index infinity) 4^n/(3^n-1)
  4. Calculus

    Test for convergence or divergence. Indicate the test that was used and justify your answer. Sigma (lower index n = 2; upper index infinity) [ln(n)]/n
  5. Calculus

    Determine the convergence or divergence of the series. Indicate the test that was used and justify your answer. Sigma (lower index n = 1; upper index infinity) [(-1)^n*3^n]/(n*2^n)
  6. Calculus

    Find the values of x for which the series converges. Sigma (lower index n = 0; upper index infinity) [(x+1)/4]^n
  7. Calculus

    Identify the two series that are the same. a. Sigma (lower n = 4; upper infinity) n(3/4)^n b. Sigma (lower n = 0; upper infinity) (n+1)(3/4)^n c. Sigma (lower n = 1; upper infinity) n(3/4)^(n-1)
  8. Calculus

    Find the sum of the convergent series. Sigma (lower n = 0; upper infinity) 8*(4/5)^n
  9. Calculus

    Determine convergence or divergence for the following series. State the tests used and justify your answers. Sum (infinity, n=1) 1/(1+e^-n) Sum (infinity, n=1) (2*4*6...2n)/n! Sum (infinity, n=0) (n-6)/n Sum (infinity, n=0) (n-6)/n! …
  10. calculas 1

    Use upper and lower sums to approximate the area of the region using the given number of subintervals (of equal width). (Round your answers to three decimal places.) y = 7/x number of interval between are 5 upper sum= lower sum=

More Similar Questions