posted by Lena .
The Go’ value for the hydrolysis of glucose-6-phosphate is -13.8 kJ/mol. Assuming a concentration of 4 mM for this molecule, what would the phosphate concentration be at equilibrium (G = 0). Remember to convert kJ to J.
The hydrolysis of glucose-6-phosphate produces phosphate and glucose, so I will have to assume that glucose and phosphate are at equal concentrations for the reaction in order to do this. If you were given the information for glucose, let me or someone else know.
that are all the information given
Okay then this what you I believe you should do:
Glucose-6-phosphate----> Glucose + Pi
Since the reaction is at equilibrium, ∆G =0.
Plug in your values and solve for x
Take the square root of your answer to solve for one x.
x=Pi concentration=glucose concentration
*****The concentration of glucose and Pi will be the same.
In the manipulation of the equation, replace