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posted by Heidi Saturday, February 9, 2013 at 11:55pm.
A downward force of 5.1 N is exerted on a -7.3 mcirco C charge. What is the magnitude of the electric field at this point?
E=F/q so E=(5.1N)/(7.3x10^-6 C) = 6.99x10^5 N/C 7.3 microC = 7x10^-6 C
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