west chester university
posted by kayla .
A ball is thrown vertically upward, which is the positive direction. A little later it returns to its point of release. The ball is in the air for a total time of 8.26 s. What is its initial velocity? Neglect air resistance.

Its vertical distance is given by a parabola.
Since we know the tintercepts are 0 and 8.26 ,and we know a =4.9 m/sec^2
the equation is
s = 4.9t(t8.26)
= 4.9t^2 + 40.472 , where m is in metres
v = 9.8t + 40.472
when t = 0 , v = 40.472
initial velocity is 40.72 m/sec
Wow, that is quite a toss!
BTW, if you are working in feet,
a = 32 ft/sec^2
duplicate the above steps, not much has to be changed.
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