Physics
posted by Ted
The force required to stretch a Hooke’slaw
spring varies from 0 N to 63.5 N as we stretch
the spring by moving one end 5.31 cm from
its unstressed position.
Find the force constant of the spring.
Answer in units of N/m

Henry
K = 63.5N/0.0531m = 1196N/m.
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