Physics
posted by Anonymous .
A projectile is fired at 65.0° above the horizontal. Its initial speed is equal to 37.5 m/s. Assume that the freefall acceleration is constant throughout and that the effects of the air can be ignored.At what time after being fired does the projectile reach this maximum height?

Physics 
Henry
Vo = 37.5m/s @ 65o.
Yo = 37.5*sin65 = 34 m/s.
Y = Yo + gt.
t = (YYo)/g = (034)/9.8 = 3.47 s.
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