Calculus
posted by Tori .
Use the intermediate value therom to show that there is a root of the given equation in the specified interval.
x^57=2(25x); (2,3)
Please explain for understanding and show work, Thank you in advance :)

x^5  7 = 50  2x
x^5 + 2 x  57 = 0
y = x^5 + 2 x  57
if x = 2
y = 32 +4  57 = negative number
if x = 3
y = 81*3 + 6  57 = positive number
the polynomial is continuous so somewhere in there y was zero
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