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Calculus help!

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A ball is shot into the air from a bridge, and its height, y, in feet, above the ground t seconds after it is thrown is given by y=f(t) = −16t2 + 55t + 33.
What is the average velocity of the ball during the first second? Round your answer to two decimal places.

  • Calculus help! -

    the average velocity will be distance traveled divided by the time interval

    y(0) = 33
    y(1) = 72
    avg v = 72-33 = 39

    Or,
    v = -32t + 55
    avg is the ∫[0,1]v(t)/(1-0)

    Note that the value is just that figured above.

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