At an instant when a soccer ball is in contact with the foot of a player kicking it, the horizontal or x component of the ball's acceleration is 780 m/s2 and the vertical or y component of its acceleration is 1160 m/s2. The ball's mass is 0.38 kg. What is the magnitude of the net force acting on the soccer ball at this instant?

To find the magnitude of the net force acting on the soccer ball, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.

In this case, we know the mass of the soccer ball is 0.38 kg. We are also given the x-component of the acceleration, which is 780 m/s^2, and the y-component of the acceleration, which is 1160 m/s^2.

The net acceleration of the soccer ball can be found using the Pythagorean theorem, as the x- and y-components of acceleration form a right triangle. The net acceleration (a) can be calculated as follows:

a = sqrt((ax)^2 + (ay)^2)
= sqrt((780 m/s^2)^2 + (1160 m/s^2)^2)

Calculating this, we find that the net acceleration is approximately 1407.37 m/s^2.

Now, we can use Newton's second law to find the net force (F) acting on the soccer ball:

F = m * a
= 0.38 kg * 1407.37 m/s^2

Calculating this, we find that the magnitude of the net force acting on the soccer ball at this instant is approximately 534.34 N (Newton).