Physics

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A 6 kg grinding wheel of radius 0.2 m rotates at a constant rotational frequency of 4 rad/s when an object makes contact with the outer edge of the wheel. Friction causes the wheel to stop in 2 seconds. What is the average torque on the wheel by the frictional force?

  • Physics -

    Torque = (Moment of Inertia)*(Angular deceleration)

    The moment of inertia is
    I = (1/2)*M*R^2 = 3*(0.2)^2
    = 0.12 kg*m^2

    Angular deceleration = (4 rad/s)/2s = 2 rad/s^2

    Torque = 0.12 * 2 = 0.24 Newton-meter

  • Physics -

    Is actualy A 6 kg grinding wheel of radius 0.2 m rotates at a constant rotational frequency of 4(pi) rad/s when an object makes contact with the outer edge of the wheel. Friction causes the wheel to stop in 2 seconds. What is the average torque on the wheel by the frictional force?
    ANS = 0.754

  • Physics -

    .754

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