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If 20.5 mL of a 5.256 M solution of benzoic acid is used in an experiment similar to experiment 4, how many grams of benzoic acid is in the starting solution? (molar mass of benzoic acid = 122.12 g/mol) Be sure to pay attention to significant figures. The answers are all in grams

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    I have no idea what experiment 4 is nor what role the benzoic acid played in the experiment. However, g benzoic acid in the 20.5 mL is
    M x L x molar mass = grams.
    5.256M x 0.0205 L x 122.12 = ?grams.

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