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Calculus

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show that the tangent to the curve f:f(x)= x^2-x at the point p1(0,0) is perpendicular to the tangent to the curve at p2(1,0)

  • Calculus -

    f ' (x) = 2x - 1
    so at (0,0) slope = 2(0) -1 = -1
    and at (1,0) slope = 2(1) - 1 = +1

    since the slopes are negative reciprocals of each other the two tangents are perpendicular.

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