#1.) A 3.0 kg computer printer is pushed across a desk at a rate of 0.6m/ s2 (towards the right). Determine the force applied to the printer
#2.) If a 0.9 kg apple falls from a tree and hits the ground with a force of 8.82 N calculate the acceleration of the apple.
#3.) Calculate the mass of the truck that has a weight equal to 19600 N on Earth.
#4.) A car's airbag will activate and increase the stopping time of a passenger time from 1.0 x 10 -2s to 3.0 x 10 -1s. If the person in the car has a mass of 70.0 kg and the car is travelling at 100km/h (approximately 28 m/s). Determine the magnitute of force that the person will exert on the airbag.
Please show how you got all your answers including the answers.
Sure! I'll explain how to solve each of the given problems step by step.
#1.) To determine the force applied to the printer, we can use Newton's second law of motion, which states that force (F) is equal to the mass (m) of an object multiplied by its acceleration (a). In this case, the mass of the printer is given as 3.0 kg, and the acceleration is given as 0.6 m/s^2. Therefore, the force applied to the printer can be calculated as follows:
F = m * a
F = 3.0 kg * 0.6 m/s^2
F = 1.8 N
So, the force applied to the printer is 1.8 Newtons.
#2.) To calculate the acceleration of the apple when it hits the ground, we can use Newton's second law again. The force acting on the apple when it hits the ground is given as 8.82 N, and the mass of the apple is given as 0.9 kg. We can rearrange the equation to solve for acceleration (a):
F = m * a
a = F / m
a = 8.82 N / 0.9 kg
a ≈ 9.8 m/s^2
The acceleration of the apple when it hits the ground is approximately 9.8 m/s^2.
#3.) To calculate the mass of the truck that has a weight of 19600 N on Earth, we can use Newton's second law again in the form of the equation:
F = m * g
where F is the weight of the truck, m is the mass, and g is the acceleration due to gravity. On Earth, the value of acceleration due to gravity is approximately 9.8 m/s^2. Plugging in the given values, we can solve for the mass (m):
F = m * g
19600 N = m * 9.8 m/s^2
m = 19600 N / 9.8 m/s^2
m ≈ 2000 kg
So, the mass of the truck is approximately 2000 kilograms.
#4.) To determine the magnitude of force that the person exerts on the airbag, we can use the equation for force:
F = m * Δv / Δt
where F is the force, m is the mass of the person, Δv is the change in velocity, and Δt is the change in time. The mass of the person is given as 70.0 kg, the initial velocity of the car is given as 28 m/s, the final time is 3.0 x 10^-1 s, and the initial time is given as 1.0 x 10^-2 s. To calculate the change in velocity, we subtract the initial velocity from the final velocity:
Δv = final velocity - initial velocity
Δv = 0 - 28 m/s
Δv = -28 m/s
Now we can plug the given values into the equation:
F = m * Δv / Δt
F = 70.0 kg * (-28 m/s) / (3.0 x 10^-1 s - 1.0 x 10^-2 s)
F ≈ -19600 N/s
So, the magnitude of force that the person exerts on the airbag is approximately 19600 Newtons.