A person who is 1.4 m tall throws a ball with a speed of 4.2 m/s at an angle of 25 degrees above the horizontal. What are the x and y components of the velocity (in m/s) of the ball the instant before it strikes the ground? The acceleration due to gravity is 10 m/s2
These questions are all the same. You try.
To find the x and y components of the velocity of the ball before it strikes the ground, we can use the equations of motion and some trigonometry.
First, let's calculate the initial velocity components.
The x component of the velocity (Vx) can be found using the initial speed and the angle:
Vx = initial speed * cos(angle)
Vx = 4.2 m/s * cos(25°)
Vx = 4.2 m/s * 0.9063 (cosine of 25°)
Vx ≈ 3.8083 m/s
The y component of the velocity (Vy) can be found using the initial speed and the angle:
Vy = initial speed * sin(angle)
Vy = 4.2 m/s * sin(25°)
Vy = 4.2 m/s * 0.4230 (sine of 25°)
Vy ≈ 1.7751 m/s
So, the x component of the velocity is approximately 3.8083 m/s, and the y component of the velocity is approximately 1.7751 m/s.