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If the average (xbar) on an assignment in a class was 82% with a standard deviation (s) of 4.8, what is the z-score for someone scoring 75% (round to the one hundredths place or two decimal places)?

  • Biostats -

    Z = (score-mean)/SD

    Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.

  • Biostats -

    82-75= 7/4.8=1.45

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