college general chemistry

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Calculate the volume of a rectangular solid with a thickness of 0.750 cm and an area of 8.25 cm2

• college general chemistry -

0.750cm*8.25cm^= volume in cm^3

• college general chemistry -

Devron that's not right it said incorrect

• college general chemistry -

The volume of a rectangular solid is w*l*h= cm*cm*cm=cm^3

I calculated 6.19cm^3, is this what you calculated when performing the calculations?

• college general chemistry -

Unless they asked you to convert it to different units, I am not sure what to tell you at this time.

• college general chemistry -

google, area* thickness= volume and relook at the problem to come up with an answer.

• to Amber---college general chemistry -

Don't leave us in the dark. Saying it is wrong without showing your work leaves us with no alternative but to ignore your post. Show your work and we can find the error.
The correct answer is 6.1875 cc but you must round that to the correct number of significant figures.

• college general chemistry -

I am so lost I imput 6.188 because it's online homework and it said my answer was wrong you don't have to convert because it has the spot where you put the answer then cm^3

• college general chemistry -

I suspect you typed in too many significant figures.
8.25 x 0.750 = 6.18750 cc. You are allowed three significant figures (0.750 has three and 8.25 has three so three it is. So you round 6.18750 to three places. I would round that to 6.19 cc. Try 6.19 cc. That's the right answer.

• college general chemistry -

it's right thank you so much so i just need to learn my significant figures yeah

• college general chemistry -

Good. You also learned something else. If you had typed in your work about 2.5 hours ago when we first responded, we would have caught the error then and you would have saved more than 2 hours of your valuable time.

• college general chemistry -

That should have been the question that I asked instead of posting the correct answer with the number of correct sig figs. Dr. Bob222 is excellent, and I l have been learning from him as well.

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