posted by .

How do you solve 7√3 + √3? I really need help.

7 apples + an apple = 8 apples
7x + x = 8x
7√3 + √3 = 8√3

imagine there's a "1" in front of √3, making it 1√3

so,just as 7x + 1x = (7+1)x = 8x

7√3 + 1√3 = 8√3

Ohhh, Thank You!!!! :D

But what if the numbers aren't the same as 2√8 - 3√2? Do you make them equivalent?

Sometimes you can

√8 = 2√2 so
2√8-3√2 = 4√2-3√2 = √2

But if you have something like

2√5 + 4√7 you're out of luck

That's what I don't get. How can √8 be equal to 2√2?

My calculator tells me they are the same.

√(ab) = √a√b
√8 = √(4*2) = √4√2 = 2√2

## Similar Questions

1. ### Algebra 2: Radicals URGENT!!

Could some kind, saintly soul help me solve this problem?
2. ### Math

I need someone to check my homework answers. I don't really know this stuff but i'm trying to do better in math this year. I didn't understand how to do some either. 1. √12 I got 2√3 2. √9a^3 I got 3a 3. √8 …
3. ### Algebra

How would i complete these problems? 1. (√6mn)^5 2. ^3√16x - ^3√2x^4 3.^4√x • ^3√2x 4. ^3√72x^8 5. √63a^5b • √27a^6b^4 and are these problems correct?
4. ### Math

Find an equation of the line that bisects the obtuse angles formed by the lines with equations 3x-y=1 and x+y=-2. a. (3√2 +√10)x-(√10 + √2)y-2√10+√2=0 b. (3√2 - √10)x+(√10 - √2)y+2√10+√2=0 …
5. ### algebra 1

alright i have a few questions if its ok..?
6. ### maths

I will be thankfull to you if you help me to solve the below problem: 6√x-11/3√x=2√x+1/√x+6 I tried to solve the above problem like this: (6√x-11)(√x+6)=(3√x)(2√x+1) 6√x(√x+6)-11(√x+6)=(3√x)(2√x)+(3√x)(1) …