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If the freezing point of pure toluene is -95.15 oC and its freezing point depression constant is -8.38 oC/molal, what is the freezing point of a solution made by dissolving 39.338g of anthracene (C14H10) in 150.0mL of toluene? (Density of toluene = 0.8669g/mL)

  • Chemistry -

    mol anthracene = grams/molar mass
    grams toluene = volume x density
    molality = mol anthracene/kg toluene.
    delta T = Kf*m. Solve for delta T.
    Subtract from zero to find new freezing point.

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