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How much energy is required to change a 58 g ice cube from ice at −1◦C to steam at 101◦C? The specific heat of ice is 2090 J/kg ·◦ C and of water 4186 J/kg ·◦ C. The latent heat of fusion of water is 3.33 × 105 J/kg, its latent heat of vaporization is 2.26 × 106 J/kg, and the specific heat of steam is 2010 J/kg ·◦ C.
Answer in units of MJ

  • Physics -

    c₁=2090 J/kg ,c₂ = 4186 J/kg •◦ C,
    c₃ =2010 J/kg •◦ C.
    λ = 3.33•10^5 J/kg, r = 2.26• 10^6 J/kg.
    m=0.058 kg
    Q= c₁m(1)+ λm +c₂m(100) +rm + c₃m(1) = …(J)
    1MJ = 10⁶J

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