Calculus
posted by Anonymous .
Let f(x)= 6x+(4/x^2). Then the equation of the tangent line to the graph f(x) at the point (2,13) is give by y=mx+b
What is m? What is b?

get f'
evaluate at x=2
Now you have a point and a slope. Use pointslope form, convert to slopeintercept form.