precalculus
posted by yukia .
(2^(4+pi))/ 2^(1+pi)

remember, when dividing powers with the same base ...
we keep the base and subtract the exponents
4+π  (1+π)
= 4+π1π = 3
so
(2^(4+pi))/ 2^(1+pi)
= 2^3
= 8
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