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posted by paige Tuesday, January 29, 2013 at 8:54pm.
A boy sledding down a hill accelerates at 1.20 m/s2. If he started from rest, in what distance would he reach a speed of 6.10 m/s?
V^2 = Vo^2 + 2a*d d = (V^2-Vo^2)/2a d = (6.10^2-0)/2.4
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