physics
posted by paige
A boy sledding down a hill accelerates at 1.20 m/s2. If he started from rest, in what distance would he reach a speed of 6.10 m/s?

Henry
V^2 = Vo^2 + 2a*d
d = (V^2Vo^2)/2a
d = (6.10^20)/2.4
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