Post a New Question


posted by .

A boy sledding down a hill accelerates at 1.20 m/s2. If he started from rest, in what distance would he reach a speed of 6.10 m/s?

  • physics -

    V^2 = Vo^2 + 2a*d
    d = (V^2-Vo^2)/2a
    d = (6.10^2-0)/2.4

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question