posted by Fai .
5ml of 8N HN03, 4.8ml of 5N HCL and a certain volume of 17M H2s04 are mixed together and made up to 2 liter 30ml of this acid mixture exactly neutralize 42.9ml of na2c03, 10 H2O in 100ml of water. Calculate the amount of sulphate 10m in gm present in solution
The 6.5gm who help
Your post makes no sense to me. (sulphate 10m in gm??). The 6.5gm who help?