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Let f(x)=3x^4-2x^2+3

a) find f'(x)
Answer: f'(x)=12x^3-4x

b) find the slope of the line tangent to the graph of f at x=3.

So I got those firs two right but what I need help with is part C which is

c) find an equation of the line tangent to the graph of f at x=3

  • Calculus -

    what does ^ mean

  • Calculus -

    to the power of, for example x squared or x cubed

  • Calculus -

    surely by now you know that the line through (h,k) with slope m is

    y-k = m(x-h)

    you have h=3,m=312, and k=f(3)

    plug and chug.

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