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phy

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If a force of 80N extends a spring of natural length 8m by 0.4m what will be the length of the spring when the applied force is 100N

  • phy -

    F₁=kx₁
    F₂=kx₂
    F₁/F₂=x₁/x₂
    x₂=x₁F₂/F₁=….
    New length is L+ x₂=…

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