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posted by christ Thursday, January 24, 2013 at 10:08pm.
If a force of 80N extends a spring of natural length 8m by 0.4m what will be the length of the spring when the applied force is 100N
F₁=kx₁ F₂=kx₂ F₁/F₂=x₁/x₂ x₂=x₁F₂/F₁=…. New length is L+ x₂=…
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