The average atomic mass of iridium is 192.22u, if iridium-191 has an atomic mass of 190.961u and an isotopic abundance of 37.3% and iridium-193 is the only other natural occuring isotope, what is the atomic mass of iridium-193?
I tried but I don't think I have the right answer..(I get 12.01???
Please help I have an exam today
The answer is simple:
To get the isotopic abundance of iridium 193, you subtract the isotopic abundance of iridium 191 from 100.
Then, you substitute the formula with the figures to get:
192.22U= (190.961* 0.373) + (0.627*m2)
If you calculate accurately, you get 121/0.627 = m2
And that gave me, 192.9U
where did u get 627 from?
Surely not 12.01 -- That's carbon.
.373*190.96 + .627x = 192.22
x = 192.97
Hence the Ir-193 moniker
There are only two isotopes. If Ir-191 is 37.3%, Ir-193 is 62.7%
Think back back back to Algebra I. This is just a mixture problem.
oh 100-37.3 okokok thxx
Well, it seems like you're feeling a bit stuck, but don't worry, I'm here to help! Let's unravel the mystery of iridium-193's atomic mass together, shall we?
To find the atomic mass of iridium-193, we'll use the information given about iridium-191 and the overall average atomic mass of iridium.
The average atomic mass of iridium is weighted based on the abundance of each isotope. We know that iridium-191 has an atomic mass of 190.961u and an isotopic abundance of 37.3%.
To find out the isotopic abundance of iridium-193, simply subtract the abundance of iridium-191 from 100%, since it's the only other natural occurring isotope. In this case, it will be 100% - 37.3% = 62.7%.
Now, let's use this information and do some math. Since we have the average atomic mass of iridium (192.22u), we will set up an equation:
Average atomic mass = (atomic mass of iridium-191 * abundance of iridium-191) + (atomic mass of iridium-193 * abundance of iridium-193)
Plugging in the values we have:
192.22u = (190.961u * 0.373) + (atomic mass of iridium-193 * 0.627)
Now, to solve for the atomic mass of iridium-193, we can rearrange the equation:
atomic mass of iridium-193 = (192.22u - 190.961u * 0.373) / 0.627
Calculating this out should give you the correct answer. Remember, the atomic mass of iridium-193 won't be 12.01, that's carbon's atomic mass! Good luck on your exam, and remember to keep your atomic sense of humor intact!
To find the atomic mass of iridium-193, we need to first calculate the atomic mass contribution from iridium-191, then subtract it from the average atomic mass of iridium.
First, let's calculate the atomic mass contribution from iridium-191:
Atomic mass contribution from iridium-191 = (atomic mass of iridium-191) * (abundance of iridium-191)
Atomic mass contribution from iridium-191 = 190.961u * 0.373
Calculating this gives us:
Atomic mass contribution from iridium-191 = 71.257573u
Next, we need to subtract this contribution from the average atomic mass of iridium:
Atomic mass of iridium-193 = Average atomic mass of iridium - Atomic mass contribution from iridium-191
Atomic mass of iridium-193 = 192.22u - 71.257573u
Calculating this gives us:
Atomic mass of iridium-193 = 120.962427u
Therefore, the atomic mass of iridium-193 is approximately 120.962u, not 12.01.