Physics

posted by .

A hotair balloonist, rising vertically with a constant speed of 5.00 m/s, releases a sadndbag at the instant the balloon is 40.0 m above the ground. after it is released, the sandbag encounters no appreciable air drag. a. compute the position and velocity of the sandbag at .250 s and 1.00 s after its release. b. how many seconds after its release will the bag strike the ground? C. how fast is it moving as it strikes the ground? d. what is the greatest height above the ground that the sandbag reaches?

  • Physics -

    Vi=0 in the Y-direction of the bag going down, a=g=9.8m/s^2, d=40m. Even if it is rising at 5m/s, the velocity going down will not no be affected by the velocity going up. Since the velocity is 0, initially, and it accelerates down at a rate of 9.8m/s^2, multiply 9.8m/s^2 by 0.250s to give you the velocity at this time interval; notice that one of the s's cancel to give you units of m/s which is velocity at that time. In one second, the sand bag accelerated by 9.8m/s^2. Since the initial velocity (Vi) is 0 at the time of release, in one second the velocity is equal to gravity=9.8m/s. Use the formula (Vf)^2=(Vi)^2 +2ad to find the final velocity (Vf). Since Vi=0, the formula turns into Vf=(2ad)^1/2=(2(9.8m/s^2)(40m))^1/2. Once you compute the Vf, plug in Vf, Vi=0, and a=9.8m/s^2 into one of your other kinematic equations (Vf=Vi+at) and solve for time (t). Since the bag is released at 40m, it only reaches a max height of 40m.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Physics

    A hot-air balloonist, rising vertically with a constant velocity of magnitude v = 5.00 m/s, releases a sandbag at an instant when the balloon is a height h = 40.0 m above the ground. After it is released, the sandbag is in free fall. …
  2. Physics 1

    A hot-air balloonist, rising vertically with a constant velocity of magnitude v = 5.00 m/s, releases a sandbag at an instant when the balloon is a height h = 40.0 m above the ground. After it is released, the sandbag is in free fall. …
  3. physics

    a hot air balloonist, rising vertically with a constant velocity of magnitude 5m/s releases a sandbag at an instant when the balloon is 40m above the ground. after it is released, the sandbag is in free fall. a) compute position at …
  4. physics

    A balloonist, riding in the basket of a hot air balloon that is rising vertically with a constant velocity of 10.1 m/s, releases a sandbag when the balloon is 43.4 m above the ground. Neglecting air resistance, what is the bag's speed …
  5. Physics

    A balloonist, riding in the basket of a hot air balloon that is rising vertically with a constant velocity of 9.5 m/s, releases a sandbag when the balloon is 44.3 m above the ground. Neglecting air resistance, what is the bag's speed …
  6. Physics

    A hotair balloonist, rising vertically with a constant speed of 5.00 m/s, releases a sadndbag at the instant the balloon is 40.0 m above the ground. after it is released, the sandbag encounters no appreciable air drag. a. compute the …
  7. physical science

    A hot air balloon is rising upwards at a constant velocity of 5 m/s . When the balloon is 60 m above the ground , a sand bag is released from it and allowed to free fall . Ignore the effect of air resistance and assume that the balloon …
  8. Physics

    A hot-air balloon is rising upwards at a constant velocity of 5m.s . When the balloon is 100m above the ground , a sandbag is dropped from it. Will the velocity of the hot-air balloon increase , decrease or remain the same immediately …
  9. Physics

    1 A hot-air balloon is rising upwards at a constant velocity of 5m.s When the balloon is 100m above the ground, a sandbag is dropped from it. 1.1 what is the velocity of the sandbag when its displacement is zero. 1.2 Determine the …
  10. science

    2.2. A hot air balloonist, rising vertically with a constant velocity of magnitude 5.00m/s releases a sandbag at an instant when the balloon is 40.0m above the ground as shown. After it is released, the sandbag is in free fall. 1. …

More Similar Questions