College Algebra
posted by Audrey .
The load L a horizontal beam can safely support varies jointly as the width w and the square of the depth d and inversely as the length l. If a 12foot beam with width 6 inches and depth 8 inches safely supports 600 pounds, how many pounds can a 14foot beam that has width 5.5 inches and depth 4 inches be expected to support? Round to the nearest pound. Assume the two beams are made of the same material.

"The load L a horizontal beam can safely support varies jointly as the width w and the square of the depth d and inversely as the length l"
 >Load = k(wd^2/L)
given :
L = 12, w = 6inches or 1/2 , d = 8 inches or 2/3, load = 600
600 = k(1/2)(4/9) /12
(1/54)k = 600
k = 32400
Load = 32400(wd^2/L)
for the case L = 14 , w = 11/24 , d = 1/3
Load = 32400(11/24)(1/9)/14 = 117.857 or 118 to the nearest pound
check my arithmetic, easy to make a mistake on this one. 
Show me the steps in doing this problem
30ax15ay+42x21y
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