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A pharmacist has 40% and 60% iodine solutions on hand. How many liters of each iodine solution will be required to produce 4 liters of a 50% iodine.

  • algebra -

    .4x + .6(5-x) = .5(4)

    so, 5L of 40% and 5L of 60%

    makes sense, since 50% is halfway between the two.

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