Physics
posted by Big Poppa Smurf .
A 3.6 kg block initially at rest is pulled to the right along a horizontal, frictionless surface by a constant, horizontal force of 18.2 N. Find the speed of the block after it has moved 2.7 m. Answer in units of m/s

Vi=0, D=2.7m, and Vf=?. Use F=ma= 18.2N=3.6Kg*(a) and solve for the acceleration (a). Once you have solved for a. Plug in the numbers into one of the kinematic equations Vf^2=Vi^2+2ad. I haven't worked out the math, but you should het the right answer.

F=MA>
sqrt(2AX)
distance is X
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