physics

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Consider two vectors where F1 = 53 N, F2 =
81 N, 1 = 320 , and 2 = 13 ,measured from
the positive x axis with the counter-clockwise. What is the magnitude of the resulting vector?

  • physics -

    1 is angle 1 and 2 is angle 2

  • physics -

    α1 =360⁰-320⁰ =40⁰
    F(x) =F1(x)+F2(x)
    =F1cosα1 + F2cosα2 =
    =53•cos40 +81•cos13 =40.6+78.9=119.5 N

    F(y) =F1(y)+F2(y)
    = - F1sinα1 + F2sinα2 =
    = - 53•sin40 +81•sin13 =
    = - 34.07 +18.22 = - 15.85 N
    F=sqrt{F(x)²+F(y)²} =
    =sqrt{119. 5²+15.85²} =120.5 N

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