posted by manjula .
if (l1,m1,n1),(l2,m2,n2),(l3,m3,n3) are the direction cosines of three mutual perpendicular lines,show that the line whose direction ratios area l1+l2+l3,m1+m2+m3,n1+n2+n3 make equal angles with them
Because the first three lines are mutually perpendicular, dot products of pairs of lines are zero.
l1*l2+m1*m2+n1*n2 = 0
l2*l3+m2*m3+n2*n3 = 0
l1*l3+m1*m3+n1*n3 = 0
Finally, using the above equations, and another dot product, show that the cosine of the angle between the fourth vector and any of the first three vectors is the same.
listen to me dear.solve these six equations.l1l2+m1m2+n1n2=0,l2l3+m2m3+n2n3=0and l1l3+m1m3+n1n3=0...with these solve theselil2+m1m2+n1n2=l2l3+m2m3+n2n3=l1l3+m1m3+n1n3
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