math pre calc
posted by Rosagne .
solve sin theta = 1/2,90 degrees less than theta less than 180 degrees

make sure your calculator is set to degrees
2nd
sin
(1/2.9)
= 20.17
You want the angle between 0 and 180, that is in the I or II quadrant.
20.17° is in quadrant I
the angle in quadrant II would be 180  20.17 = 159.83°
check:
take the sine of each of those angles and compare it to 1/2.9
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