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An athlete whirls a 6.6 kg hammer tied to
the end of a 1.2 m chain in a horizontal circle.
The hammer moves at the rate of 0.432 rev/s.
What is the centripetal acceleration of the
hammer? Assume his arm length is included
in the length given for the chain.
Answer in units of m/s
What is the tension in the chain?
Answer in units of N

  • physics -

    centripetal acceleration is v^2/r

    The tension in the chain is m*v^2/r

    where v is the speed = 2*PI*r*f

    where f is the frequency; r is the radius; m is the mass

    v = 2*PI*1.2*0.432

    solve for the acceleration and tension using the above equations

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